3.20 \(\int \sqrt {c \sec (a+b x)} \, dx\)

Optimal. Leaf size=38 \[ \frac {2 \sqrt {\cos (a+b x)} F\left (\left .\frac {1}{2} (a+b x)\right |2\right ) \sqrt {c \sec (a+b x)}}{b} \]

[Out]

2*(cos(1/2*b*x+1/2*a)^2)^(1/2)/cos(1/2*b*x+1/2*a)*EllipticF(sin(1/2*b*x+1/2*a),2^(1/2))*cos(b*x+a)^(1/2)*(c*se
c(b*x+a))^(1/2)/b

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Rubi [A]  time = 0.02, antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3771, 2641} \[ \frac {2 \sqrt {\cos (a+b x)} F\left (\left .\frac {1}{2} (a+b x)\right |2\right ) \sqrt {c \sec (a+b x)}}{b} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[c*Sec[a + b*x]],x]

[Out]

(2*Sqrt[Cos[a + b*x]]*EllipticF[(a + b*x)/2, 2]*Sqrt[c*Sec[a + b*x]])/b

Rule 2641

Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticF[(1*(c - Pi/2 + d*x))/2, 2])/d, x] /; FreeQ
[{c, d}, x]

Rule 3771

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Dist[(b*Csc[c + d*x])^n*Sin[c + d*x]^n, Int[1/Sin[c + d
*x]^n, x], x] /; FreeQ[{b, c, d}, x] && EqQ[n^2, 1/4]

Rubi steps

\begin {align*} \int \sqrt {c \sec (a+b x)} \, dx &=\left (\sqrt {\cos (a+b x)} \sqrt {c \sec (a+b x)}\right ) \int \frac {1}{\sqrt {\cos (a+b x)}} \, dx\\ &=\frac {2 \sqrt {\cos (a+b x)} F\left (\left .\frac {1}{2} (a+b x)\right |2\right ) \sqrt {c \sec (a+b x)}}{b}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 38, normalized size = 1.00 \[ \frac {2 \sqrt {\cos (a+b x)} F\left (\left .\frac {1}{2} (a+b x)\right |2\right ) \sqrt {c \sec (a+b x)}}{b} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[c*Sec[a + b*x]],x]

[Out]

(2*Sqrt[Cos[a + b*x]]*EllipticF[(a + b*x)/2, 2]*Sqrt[c*Sec[a + b*x]])/b

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fricas [F]  time = 0.68, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\sqrt {c \sec \left (b x + a\right )}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sec(b*x+a))^(1/2),x, algorithm="fricas")

[Out]

integral(sqrt(c*sec(b*x + a)), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {c \sec \left (b x + a\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sec(b*x+a))^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(c*sec(b*x + a)), x)

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maple [C]  time = 0.92, size = 98, normalized size = 2.58 \[ -\frac {2 i \sqrt {\frac {c}{\cos \left (b x +a \right )}}\, \left (-1+\cos \left (b x +a \right )\right ) \sqrt {\frac {1}{\cos \left (b x +a \right )+1}}\, \sqrt {\frac {\cos \left (b x +a \right )}{\cos \left (b x +a \right )+1}}\, \EllipticF \left (\frac {i \left (-1+\cos \left (b x +a \right )\right )}{\sin \left (b x +a \right )}, i\right ) \left (\cos \left (b x +a \right )+1\right )^{2}}{b \sin \left (b x +a \right )^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*sec(b*x+a))^(1/2),x)

[Out]

-2*I/b*(c/cos(b*x+a))^(1/2)*(-1+cos(b*x+a))*(1/(cos(b*x+a)+1))^(1/2)*(cos(b*x+a)/(cos(b*x+a)+1))^(1/2)*Ellipti
cF(I*(-1+cos(b*x+a))/sin(b*x+a),I)*(cos(b*x+a)+1)^2/sin(b*x+a)^2

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {c \sec \left (b x + a\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sec(b*x+a))^(1/2),x, algorithm="maxima")

[Out]

integrate(sqrt(c*sec(b*x + a)), x)

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mupad [B]  time = 0.20, size = 35, normalized size = 0.92 \[ \frac {2\,\sqrt {\cos \left (a+b\,x\right )}\,\sqrt {\frac {c}{\cos \left (a+b\,x\right )}}\,\mathrm {F}\left (\frac {a}{2}+\frac {b\,x}{2}\middle |2\right )}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c/cos(a + b*x))^(1/2),x)

[Out]

(2*cos(a + b*x)^(1/2)*(c/cos(a + b*x))^(1/2)*ellipticF(a/2 + (b*x)/2, 2))/b

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {c \sec {\left (a + b x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sec(b*x+a))**(1/2),x)

[Out]

Integral(sqrt(c*sec(a + b*x)), x)

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